P(x)=20x^2-240x

Solution for P(x)=20x^2-240x equation:

(P)=20P^2-240P

We move all terms to the left:

(P)-(20P^2-240P)=0

We get rid of parentheses

-20P^2+P+240P=0

We add all the numbers together, and all the variables

-20P^2+241P=0

a = -20; b = 241; c = 0;
Δ = b2-4ac
Δ = 2412-4·(-20)·0
Δ = 58081
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$P_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$P_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{58081}=241$
$P_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(241)-241}{2*-20}=\frac{-482}{-40}
=12+1/20
$
$P_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(241)+241}{2*-20}=\frac{0}{-40}
=0
$